Here's something useful for innumerates like myself which I found on Yahoo! Watch it:
I tried multiplying a 3-digit number by a 2-digit one using the technique taught by the video, but of course, increased the table into a 6-cell thingy and still got a correct result. Will try it with more digit-numbers later.
Talkin' 'bout stuff over steaming cups of coffee. Grab a seat and be part of the chit-chat.
